Sedona stargazing: book a tour, or just find a dark road?

Evening Sky Tours lists 2 bookable tours, priced $117 USD per adult. The least expensive is Sedona Stargazing Tour ($117 USD per adult, 1 hour 10 minutes); the most expensive is Private Stargazing Tour ($1200 USD per group (up to 6 people), 1 hour 10 minutes). You can book online or by phone. Phone: (928) 203-0006. The sky is free — Sedona holds an International Dark Sky designation and a dark pullout costs nothing. What the ticket below buys, per the operator's own pages: telescope viewing of galaxies, clusters, nebulae and planets, an astronomer running laser-guided constellation education, and a reserved dark-sky site a short drive from town with directions sent at booking. Forum travellers who went DIY and loved it usually had their own optics and a moonless night; the moon phase on your dates matters either way and no tour controls it. Every figure here was read from the operators' own websites and carries the date it was checked; none of these Sedona listings has been independently verified yet. This answer was last reviewed on August 29, 2026.

Every Evening Sky Tours tour

Bookable tours. Prices and durations checked August 29, 2026.
TourDurationPrice (USD)How to book
Sedona Stargazing Tour1 hour 10 minutes$117 USD per adultonline or by phone
Private Stargazing Tour1 hour 10 minutes$1200 USD per group (up to 6 people)online or by phone

Children 12 and under are $76 on the shared tour. The tour runs one hour and ten minutes, with telescope viewing of galaxies, clusters, nebulae and planets plus laser-guided constellation education.

The sold-out pattern

Multiple threads show stargazing tours selling out around spring weekends — and this index does not track availability, so the operator's own calendar is the source of truth. Evening jeep alternatives exist too: the night-tours question page lists the stargazing and full-moon jeep runs by name with their prices.

About this draft

This page is a draft answering the most-repeated question the mining pass found (sources in docs/QUESTIONS.md). It draws only on compiled, unverified operator records and has not yet been reviewed by the editor. Corrections are free: report an error from any page.

The records behind this answer


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